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1=0.5*h^2
We move all terms to the left:
1-(0.5*h^2)=0
We get rid of parentheses
-0.5*h^2+1=0
We add all the numbers together, and all the variables
-0.5h^2+1=0
a = -0.5; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-0.5)·1
Δ = 2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2}}{2*-0.5}=\frac{0-\sqrt{2}}{-1} =-\frac{\sqrt{}}{-1} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2}}{2*-0.5}=\frac{0+\sqrt{2}}{-1} =\frac{\sqrt{}}{-1} $
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